(d) Where lightweight concrete is used, λ shall not exceed 0.75 unless fct is specified (see 8.6.1). 6 and smaller bars and deformed wires, ψs = 0.8. However, the product ψtψe need not be greater than 1.7. For uncoated and zinc-coated (galvanized) reinforcement, ψe = 1.0. For all other epoxy-coated bars or wires, ψe = 1.2. (b) For epoxy-coated bars or wires with cover less than 3db, or clear spacing less than 6db, ψe = 1.5. of fresh concrete is cast below the development length or splice, ψt = 1.3. (a) Where horizontal reinforcement is placed such that more than 12 in. Please let me know my "gap" in my knowledge on the code.ġ2.2.4 - The factors used in the expressions for development of deformed bars and deformed wires in tension in 12.2 are as follows: I've no access to, nor knowledge on, ACI318-19 though.
#Simple lap splice or a wrap splice with potting. zip#
RE: Rebar lap splice transverse reinforcement additional to shear links Agent666 (Structural) 10 Jan 21 20:06īelow is copied from ACI318-08. Wrap Around Zip Closure Re-enterable Wire & Cable Protection. To the OP, did you get your answer in amongst that? No need to double count the requirement, all transverse reinforcement contributes. R13, probably best to start your own thread in future if you have gaps in your knowledge of codes and principles involved rather than get into sideline conversations in others threads. For structural walls with lap splices comparable to those tested, the observations collected suggest that drift capacity can be as low as 0.5 for splices with minimum cover, minimum transverse reinforcement terminating in hooks, and lap splice lengths selected to reach yielding in the spliced bars. There are also specific reductions to column splices allowed if you have sufficient confinement (CL 10.7.5.2.1). Other international codes all have similar reduction factors to the development lengths and hence splice lengths where there is sufficient confinement of splices. development length clauses, in particular the Ktr factor.Įarlier versions of ACI318 had similar reductions. For example in ACI318-19 look into 25.4.2. For example in ACI take a look at how this is calculated and you'll find the answer. Wrap a fine, flat shielding braid onehalf lapped over the splice extending 1/2 inch (12 mm) onto the metallic shielding. The splice length is a function of the development length.
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